Board Jammu & Kashmir Board of School Education [JKBOSE]
Class 10th/X
Subject Mathematics/Maths
Download Question Bank
Document Type PDF
Official Website https://jkbose.nic.in/index.html

JKBOSE Class 10th Maths Question Bank

Download Jammu & Kashmir Board of School Education [JKBOSE] Class 10th Maths Question Bank Online

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Download JKBOSE Class 10th Maths Question Bank

JKBOSE Class 10th Maths Question Bank Chapter 1 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 2 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 3 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 4 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 5 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 6 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 7 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 8 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 9 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 10 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 11  Download Here
JKBOSE Class 10th Maths Question Bank Chapter 12 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 13 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 14 Download Here
JKBOSE Class 10th Maths Question Bank Chapter 15 Download Here

Important Constructions Of A Triangle In Different Cases
Before constructing a triangle similar to a given triangle say ∆ ABC, we have to construct the ∆ ABC. For this, let us review some constructions in different cases which are given below:

Case – 1 : When three sides are given.
We use the following steps of construction:
Step – 1 : First draw base BC.
Step – 2 : By taking B and C as centers, draw two arcs of radius CA and BA respectively which intersects each other at A.
Step – 3 : Join AB and AC.
Then ABC is a required triangle.

Case – 2 : When base and alternate of a triangle are given.
Let the base of ∆ ABC be BC = m cm and Alternate is n cm. Then, we use the following steps.
Step – 1 : Draw the base BC = m cm and draw its perpendicular bisector OQ (say) which intersects BC at P (say).
Step – 2 : By taking P as center, draw an arc of radius n cm which intersects the line segment PO or extended line segment of PO at A.
Step – 3 : Join AB and AC.
Then ABC is a required triangle.

Case – 3 : When two sides and angle between them are given. Let the two sides of ∆ ABC be AB = a cm, BC = b cm and angle between them i.e. <ABC = x0. Then, we use the following steps.
Step – 1 : Draw base “AB” = “a” cm
Step – 1 : Draw a ray “BX” making an angle x0 at B and cut off BC = b cm from BX.
Step – 3 : Join “AC”. Thus ∆ ABC is required triangle

CASE – 3 : When one side and two angles are given.
Let one side of triangle ABC be AB = a cm and < A = x 0 and < B = y0
Step – 1 : Draw base AB = a cm
Step – 2 : Draw two rays AX and BY making an angle x0 at “A” and y0 at B which intersects each other at C.
Step – 3 : Join AC and CB.
Then ABC is a required triangle.

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